DiFfRG
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types.hh
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#pragma once
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namespace
DiFfRG
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{
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template
<
typename
T>
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concept
MeshIsRectangular
=
requires
(T x) { T::is_rectangular; } && T::is_rectangular;
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}
// namespace DiFfRG
DiFfRG::MeshIsRectangular
Definition
types.hh:6
DiFfRG
Definition
complex_math.hh:14
DiFfRG
include
DiFfRG
discretization
common
types.hh
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